0=x^2-150x+4400

Solution for 0=x^2-150x+4400 equation:

0=x^2-150x+4400

We move all terms to the left:

0-(x^2-150x+4400)=0

We add all the numbers together, and all the variables

-(x^2-150x+4400)=0

We get rid of parentheses

-x^2+150x-4400=0

We add all the numbers together, and all the variables

-1x^2+150x-4400=0

a = -1; b = 150; c = -4400;
Δ = b2-4ac
Δ = 1502-4·(-1)·(-4400)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-70}{2*-1}=\frac{-220}{-2}
=+110
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+70}{2*-1}=\frac{-80}{-2}
=+40
$